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4-1.Newton's Laws of Motion
easy
A body under the action of a force $\vec F = 6\hat i - 8\hat j\,N$ acquires an acceleration of $5\, ms^{-2}$. The mass of the body is ........ $kg$
A$2$
B$5$
C$4$
D$6$
Solution
Given: $\vec{F}=6 \hat{i}-8 \hat{j} N, a=5 m s^{-2}$
$\therefore F \sqrt{(6)^{2}+(-8)^{2}}=10 N$
Mass of the body, $m=\frac{F}{a}=\frac{10 N}{5 m s^{-2}}=2 k g$
$\therefore F \sqrt{(6)^{2}+(-8)^{2}}=10 N$
Mass of the body, $m=\frac{F}{a}=\frac{10 N}{5 m s^{-2}}=2 k g$
Standard 11
Physics